Software Development Exam > Software Development Questions > Consider the following JavaScript code:var x ...
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Consider the following JavaScript code:
var x = 5;
var x = 5;
function updateX() {
x = 10;
}
x = 10;
}
setTimeout(updateX, 1000);
console.log(x);
What will be the output of the above code?
What will be the output of the above code?
- a)5
- b)10
- c)Undefined
- d)This code will produce an error
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
Consider the following JavaScript code:var x = 5;function updateX() { ...
The code declares a global variable "x" with the value 5. The function "updateX" modifies the global variable "x" by assigning it the value 10. However, the function "updateX" is called asynchronously using "setTimeout" with a delay of 1000 milliseconds. Therefore, the console log is executed before the "updateX" function has a chance to modify the value of "x". Hence, the output is 5.
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Community Answer
Consider the following JavaScript code:var x = 5;function updateX() { ...
Explanation:
Initial Setup:
- The variable x is declared and assigned a value of 5.
- A function named updateX is defined, which updates the value of x to 10.
setTimeout Function:
- The setTimeout function is used to delay the execution of the updateX function by 1000 milliseconds (1 second).
Console Logging:
- The value of x is logged to the console before the setTimeout function has a chance to execute the updateX function.
Output:
- As the updateX function is executed after a delay of 1 second, the value of x remains 5 when it is logged to the console.
- Therefore, the output of the code will be 5.
Initial Setup:
- The variable x is declared and assigned a value of 5.
- A function named updateX is defined, which updates the value of x to 10.
setTimeout Function:
- The setTimeout function is used to delay the execution of the updateX function by 1000 milliseconds (1 second).
Console Logging:
- The value of x is logged to the console before the setTimeout function has a chance to execute the updateX function.
Output:
- As the updateX function is executed after a delay of 1 second, the value of x remains 5 when it is logged to the console.
- Therefore, the output of the code will be 5.
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